document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=943494>Question 943494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman is now 4 times older than her daughter. Six years ago, the product of their ages was 136. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575226 by </B><A HREF=/tutors/aboutme.mpl?userid=Merciful><B>Merciful(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Merciful><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = present daughter's age<BR>\n" );
document.write( "Then 4x = woman's present age<BR>\n" );
document.write( "x - 6 = daughter's age six years ago<BR>\n" );
document.write( "4x - 6 = woman's age six years ago<BR>\n" );
document.write( "Therefore<BR>\n" );
document.write( "( x - 6 )( 4x - 6 ) = 136<BR>\n" );
document.write( "4x^2 - 6x - 24x +   36 = 136<BR>\n" );
document.write( "4x^2 - 30x - 100 = 0<BR>\n" );
document.write( "2x^2 - 15x - 50 = 0<BR>\n" );
document.write( "( 2x +   5 )( x - 10 ) = 0<BR>\n" );
document.write( "x = 10 or x = -5/2 N/A the age can't be negative<BR>\n" );
document.write( "Daughter's age = 10<BR>\n" );
document.write( "And woman's age = 4 X 10 = 40 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );