document.write( "Question 943456: 1 car travels 15 miles an hour the 2nd car travels 30 miles an hour. The first car traveling at 15 miles an hour gets a 20 second head start. Which car will be the first to cross the finish line which is .25 miles away? What is the formula used in this math problem? \n" ); document.write( "
Algebra.Com's Answer #575194 by josmiceli(19441)\"\" \"About 
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How much of a head start did the 1st car get?
\n" ); document.write( "You have to convert \"+20+\" sec to hours
\n" ); document.write( "( seconds ) x ( minutes / second ) x ( hours / minute ) = hours
\n" ); document.write( "\"+20%2A%28+1%2F60+%29%2A%28+1%2F60+%29+=+20%2F3600+\"
\n" ); document.write( "\"+20%2F3600+=+1%2F180+\" hrs
\n" ); document.write( "-------------------------
\n" ); document.write( "Let \"+d%5B1%5D+\" = 1st car's head start in miles
\n" ); document.write( "\"+d%5B1%5D+=+r%2At+\"
\n" ); document.write( "\"+d%5B1%5D+=+15%2A%28+1%2F180+%29+\"
\n" ); document.write( "\"+d%5B1%5D+=+5%2F60+\"
\n" ); document.write( "\"+d%5B1%5D+=+1%2F12+\" mi
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\n" ); document.write( "If you start 2 stopwatches when the 2nd car leaves,
\n" ); document.write( "and you time both cars, then you let \"+t%5B1%5D+\" =
\n" ); document.write( "1st car's time in hrs, and \"+t%5B2%5D+\" = 2nd car's
\n" ); document.write( "time in hrs
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\n" ); document.write( "2nd car's equation:
\n" ); document.write( "\"+1%2F4+=+30t%5B2%5D+\"
\n" ); document.write( "\"+t%5B2%5D+=+1%2F120+\" hrs
\n" ); document.write( "--------------------
\n" ); document.write( "1st car's equation:
\n" ); document.write( "\"+1%2F4+-+1%2F12++=+15t%5B1%5D+\"
\n" ); document.write( "\"+3%2F12+-+1%2F12+=+15t%5B1%5D+\"
\n" ); document.write( "\"+15t%5B1%5D+=+1%2F6+\"
\n" ); document.write( "\"+t%5B1%5D+=+1%2F90+\" hrs
\n" ); document.write( "-------------------
\n" ); document.write( "\"+1%2F120+\" is smaller than \"+1%2F90+\", so
\n" ); document.write( "the 2nd car crosses first\r
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