document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=80138>Question 80138</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395771242/algebrahomeworkh>Gateways to Algebra and Geometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate the expression 3 + x for each number in the set<BR>\n" );
document.write( "[-1, -2, -3, -4, -5]. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57513 by </B><A HREF=/tutors/aboutme.mpl?userid=sofiyacherni><B>sofiyacherni(99)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sofiyacherni><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> so you have the equation y=3+x<BR>\n" );
document.write( "all you have to do is substitute the value in the set for x and get a number for y.<BR>\n" );
document.write( "So your first number is -1, so <BR>\n" );
document.write( "y=3+(-1)=3-1=2 do the same for the rest<BR>\n" );
document.write( "y=3+(-2)=3-2=1<BR>\n" );
document.write( "y=3+(-3)=3-3=0<BR>\n" );
document.write( "y=3+(-4)=3-4=-1<BR>\n" );
document.write( "y=3+(-5)=3-5=-2\r<BR>\n" );
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document.write( "so your set of solutions would then be {2,1,0,-1,-2}\r<BR>\n" );
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document.write( "good luck<BR>\n" );
document.write( "PS If you live in Rapid City, South Dakota area please contact me for lessons. </SPAN>\n" );
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