document.write( "Question 943360: A $6000 investment at an annual simple interest rate of 3.6% earned as much interest after one year as another investment in an account that earned 4.5% annual simple interest. How much was invested at 4.5%?
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Algebra.Com's Answer #575122 by reviewermath(1029)\"\" \"About 
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A $6000 investment at an annual simple interest rate of 3.6% earned as much interest after one year as another investment in an account that earned 4.5% annual simple interest. How much was invested at 4.5%?\r
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\n" ); document.write( "Let x = amount invested at 4.5%
\n" ); document.write( "0.045x = 0.036(6000)
\n" ); document.write( "Divide both sides by 0.045
\n" ); document.write( "x = 0.036(6000)/0.045
\n" ); document.write( "Therefore, x = $4800 [Answer]
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