document.write( "Question 943358: Please help us figure out how to get the formula.\r
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document.write( "Marisol is painting on a piece of canvas that has an area of 180 square inches. The length of the painting is 1 1/4 times the width. What are the dimensions of the painting? \n" );
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Algebra.Com's Answer #575121 by reviewermath(1029)![]() ![]() You can put this solution on YOUR website! Marisol is painting on a piece of canvas that has an area of 180 square inches. The length of the painting is 1 1/4 times the width. What are the dimensions of the painting?\r \n" ); document.write( "\n" ); document.write( "Solution: \n" ); document.write( "The mixed number 1 1/4 is equal to the improper fraction 5/4. \n" ); document.write( "Let x = width \n" ); document.write( "so (5/4)x = length \n" ); document.write( "The area of a rectangle is equal to the product of length and width. \n" ); document.write( "[(5/4)(x)](x) = 180 \n" ); document.write( "(5/4)(x^2) = 180 \n" ); document.write( "Multiply both sides by 4/5 \n" ); document.write( "x^2 = 144 \n" ); document.write( "Get the positive square root of both sides \n" ); document.write( "x = 12 \n" ); document.write( "so (5/4)(x) = 15 \n" ); document.write( "Therefore, the width is 12 inches and the length is 15 inches. \n" ); document.write( " |