document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10953>Question 10953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular building lot is twice its width. If the perimeter is 240  meters what are the dimensions of this building lot? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5751 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let width =W<BR>\n" );
document.write( "Then length = 2W (since it's twice the width)\r<BR>\n" );
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document.write( "Perimeter = 2(length+width) = 240<BR>\n" );
document.write( "2(2W+W)= 240<BR>\n" );
document.write( "2(3W)=240<BR>\n" );
document.write( "6W=240<BR>\n" );
document.write( "Dividing by 6 throughout<BR>\n" );
document.write( "W = 40<BR>\n" );
document.write( "Length = 2W = 2x40 = 80 </SPAN>\n" );
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