document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=943211>Question 943211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 53. if twice the first number minus three times the second number is 26, find both numbers. \r<BR>\n" );
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document.write( "I've tried to solve this but it doesn't look right. I've gotten x= 10.28 but I dont think that that is correct and I have yet to solve for y but I would like to make sure that the x value I got is correct or not  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575048 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=53; 2X-3Y=26<BR>\n" );
document.write( "Solve first  for X: X=53-Y<BR>\n" );
document.write( "Substitute in second<BR>\n" );
document.write( "2(53-Y)-3Y=26<BR>\n" );
document.write( "106-2Y-3Y=26 subtract 196 from each side<BR>\n" );
document.write( "-5Y=-80<BR>\n" );
document.write( " Y=16<BR>\n" );
document.write( "X+Y=53<BR>\n" );
document.write( "X+16=53<BR>\n" );
document.write( "X=37<BR>\n" );
document.write( "ANSWERS the first number is 37, the second is 16 </SPAN>\n" );
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