document.write( "Question 943192: A MACHINE IN A POTTERY FACTORY TAKES 3 MINUTES TO FORM A BOWL AND 1 MINUTE TO FORM A PLATE. The material for a bowl cost 25 cents and material for a plate costs 20 cents . If the machine runs for 8 hours (480 minutes) and exactly 44 dollars is available to spend on materials, how many bowls and plates can be produced? \r
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document.write( "So far I have 0.25x+0.20y=44 and 3x+y=8 is am I missing another equation? \n" );
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Algebra.Com's Answer #575020 by macston(5194)![]() ![]() You can put this solution on YOUR website! Let P=Plates and B=bowls \n" ); document.write( "0.25B+.20P=44; 3B+P=480 (This equation was your problem: convert all to same units) \n" ); document.write( "Solve second equation for P \n" ); document.write( "P=480-3B \n" ); document.write( "Substitute in first \n" ); document.write( "0.25B+(.2(480-3B))=44 \n" ); document.write( "0.25B+96-0.6B=44 \n" ); document.write( "96-.35B=44 Subtract 44 from each side \n" ); document.write( "96-44-0.35B=0 add .35B to each side \n" ); document.write( "52=0.35B divide each side by 0.35 \n" ); document.write( "(52/.35)=.35B/.35 \n" ); document.write( "148.6=B Number of bowls is 148.6 \n" ); document.write( "P=480-3(148.6)= 34.2 Number of plates is 34.2 \n" ); document.write( "CHECK \n" ); document.write( "Material \n" ); document.write( "0.25B+0.20P=44 \n" ); document.write( "0.25(148.6)+0.20(34.2)=44 \n" ); document.write( "37.15+6.84=44 \n" ); document.write( "43.99=44 (discrepancy due to rounding) \n" ); document.write( "Time \n" ); document.write( "3(148.6)+34.2=480 \n" ); document.write( "445.8+34.2=480 \n" ); document.write( "480=480\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |