document.write( "Question 943162: Michael is one-fourth as old as his father. Next year, their ages will total 42 years. How old is each now? \n" ); document.write( "

Algebra.Com's Answer #574972 by macston(5194) $\"\"$ $\"About$

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M=Michael's age; F=father's age=4M; F+M=40 (42-2=Sum of ages this year=40)
\n" ); document.write( "Substitute F=4M in F+M=40
\n" ); document.write( "4M+M=40
\n" ); document.write( "5M=40
\n" ); document.write( "M=8 ANSWER Michael is 8 years old
\n" ); document.write( "F=4M=4(8)=32 ANSWER Father is 32 years old
\n" ); document.write( "CHECK
\n" ); document.write( "Next year sum of ages=42
\n" ); document.write( "(F+1)+(M+1)=42 years
\n" ); document.write( "(32+1yr)+(8+1yr)=42 yrs
\n" ); document.write( "33yrs+9yrs=42 yrs
\n" ); document.write( "42 yrs=42 yrs \n" ); document.write( "

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