document.write( "Question 943106: A chemist has two solutions of HC1. One has a 40% concentration and the other has a 25% concentration. How many liters of each solutions must be mixed to obtain 129 liters of 38% solution. \n" ); document.write( "
Algebra.Com's Answer #574970 by ptaylor(2198)\"\" \"About 
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A chemist has two solutions of HC1. One has a 40% concentration and the other has a 25% concentration. How many liters of each solutions must be mixed to obtain 129 liters of 38% solution.
\n" ); document.write( "Let x= amount of 40% concentration needed
\n" ); document.write( "Then 129-x=amount of 25% concentration needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure HC1 that exists before the mixture takes place ((0.40x)+0.25(129-x))has to equal the amount of pure HC1 that exists after the mixture takes place(0.38*129). Sooooo:
\n" ); document.write( "0.40x+0.25(129-x)=0.38*129
\n" ); document.write( "0.40x+32.25-0.25x=49.02
\n" ); document.write( "0.15x=16.77
\n" ); document.write( "x=111.8 liters ---amount of 40% concentration needed
\n" ); document.write( "129-x=129-111.8=17.2 liters ----amount of 25% concentration needed\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.40*111.8+0.25*17.2=0.38*129
\n" ); document.write( "44.72+4.3=49.02
\n" ); document.write( "49.02=49.02\r
\n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor
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