document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=943104>Question 943104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the area of a rectangle is x2 + 7x + 12 square meters and the length and width of a second rectangle are 3 meters longer, what is the area of the second rectangle? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574949 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not enough info.\r<BR>\n" );
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document.write( "For example, the length could be 1 and the width could be x^2 + 7x + 12. Then the new length and width are 4 and x^2 + 7x + 15, respectively, and the new area is 4x^2 + 28x + 60.\r<BR>\n" );
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document.write( "Or, perhaps, the length and width are x+3 and x+4, and the new length and width are x+6 and x+7, and the new area is (x+6)(x+7) = x^2 + 13x + 42.\r<BR>\n" );
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document.write( "Or we could generalize this and say that the length is L and the width is (x^2 + 7x + 12)/L, then add 3 to length/width and multiply.\r<BR>\n" );
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document.write( "The problem is likely an exercise in factoring the quadratic into (x+3)(x+4), but you cannot claim that the dimensions are x+3 and x+4, and it is a poor-quality problem. </SPAN>\n" );
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