document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=943091>Question 943091</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two records and three tapes cost $31. Three records and two tapes cost$21. Find the cost of each record and each tape.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574946 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(570)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the cost of each record be x and the cost of each tape be y.<BR>\n" );
document.write( "We get two simultaneous equations in x and y.<BR>\n" );
document.write( "2x+3y=31 is the first equation.<BR>\n" );
document.write( "3x+2y=21 is the second equation.<BR>\n" );
document.write( "Multiplying the first equation with 3 we get<BR>\n" );
document.write( "6x+9y=93.........equation 3.<BR>\n" );
document.write( "Multiplying the second equation with 2 we get<BR>\n" );
document.write( "6x+4y=42.........equation 4.<BR>\n" );
document.write( "Subtracting 4 from 3 we get<BR>\n" );
document.write( "9y-4y=93-42<BR>\n" );
document.write( "5y=51<BR>\n" );
document.write( "y=10.2<BR>\n" );
document.write( "Substituting in equation 1 we get,<BR>\n" );
document.write( "2x+30.6=31<BR>\n" );
document.write( "x=0.2<BR>\n" );
document.write( "The cost of a record is $0.2(20 cents) and the cost of a tape is $10.2(10 dollars and 20 cents).<BR>\n" );
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