document.write( "Question 943060: I'm trying to sketch a graph of a semicircle and determine its center points and radius. The equation is y=square root of (-12x-x^2). My book doesn't explain semicircles. Please help! Thanks! \n" ); document.write( "
Algebra.Com's Answer #574936 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
first, write it in the form \"%28x-h%29%5E2+%2B%28y-k%29%5E2=r%5E2\" then (\"h\",\"k\") is the center and \"r\" is the radius\r
\n" ); document.write( "\n" ); document.write( "\"y=sqrt+%28-12x-x%5E2%29\" ..... square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2=-12x-x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B12x%2By%5E2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B12x%2B_%29-_%2By%5E2=0+\" complete square\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B12x%2B6%5E2%29-36%2By%5E2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B6%29%5E2%2By%5E2=36\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B6%29%5E2%2B%28y-0%29%5E2=6%5E2\"\r
\n" ); document.write( "\n" ); document.write( "center (\"-6\",\"0\") and radius of \"r=6\"\r
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\n" ); document.write( "\n" ); document.write( "To sketch, plot the center. The radius is \"r=6\" so go out \"6\" units in each direction until you have enough points to draw in the graph, or use a compass.
\n" ); document.write( "few more points\r
\n" ); document.write( "\n" ); document.write( "(\"-12\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "(\"-6\",\"6\")\r
\n" ); document.write( "\n" ); document.write( "(\"0\",\"6\")\r
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