document.write( "Question 943039: So I'm trying to graph a parabola. I already have an equation for it, I just need to find the vertex, and two other points and then graph it. The equation given is x^2 +3y=0....I have no idea what to do next? Please help! Thank you! \n" ); document.write( "
Algebra.Com's Answer #574931 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B3y=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3y=-x%5E2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-x%5E2%2F3+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-%281%2F3%29x%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "since the vertex form of parabola is \"y=a%28x-h%29%5E2%2Bk\" where \"h\" and \"k\" coordinates of the vertex, if we compare it to \"y=-%281%2F3%29x%5E2+\" we see that \"a=-1%2F3\", \"h=0\" and \"k=0\"; so, the vertex is at origin (\"0\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "make table:\r
\n" ); document.write( "\n" ); document.write( "\"x\",\"y\"\r
\n" ); document.write( "\n" ); document.write( "\"0\",\"0\"\r
\n" ); document.write( "\n" ); document.write( "\"-3\",\"-3\" .......\"y=-%281%2F3%29%28-3%29%5E2=+-%281%2F3%29%289%29\"\r
\n" ); document.write( "\n" ); document.write( "\"3\",\"-3\" .......\"y=-%281%2F3%29%283%29%5E2=+-%281%2F3%29%289%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-2\",\"-4%2F3\" .......\"y=-%281%2F3%29%28-2%29%5E2=+-%281%2F3%29%284%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2\",\"-4%2F3\" .......\"y=-%281%2F3%29%28-2%29%5E2=+-%281%2F3%29%284%29\"\r
\n" ); document.write( "\n" ); document.write( "plot points and draw a line through:\r
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