document.write( "Question 79976: Can someone show me the factoring steps that gets h^3+8/h+2 to h^2-2h+4?\r
\n" ); document.write( "\n" ); document.write( "I am particularly interested in the result of h^3+8/x+2 = (h+2)(h-2h+4)\r
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\n" ); document.write( "\n" ); document.write( "Mike
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Algebra.Com's Answer #57488 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Can someone show me the factoring steps that gets h^3+8/h+2 to h^2-2h+4?
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\n" ); document.write( "Somewhere in your algebra journey, you may have come across a \"Special factoring Formula\" section, (a good thing to know).
\n" ); document.write( "One of these formulas is called the \"Sum of Cubes\"
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\n" ); document.write( "It is often given as: u^3 + v^3 = (u + v)(u^2 - uv + v^2)
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\n" ); document.write( "h^3 + 8 is the sum of cubes but in this case u = h and v = 2; so we have:
\n" ); document.write( "\"%28%28h+%2B+2%29%28h%5E2+-+2h+%2B+4%29%29%2F%28%28h+%2B+2%29%29\"
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\n" ); document.write( "I'm sure you can see what happens now.
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