document.write( "Question 80008: I just need to know how to right this into a math problem. Here it is:\r
\n" ); document.write( "\n" ); document.write( "John now has two investments that produce a $150 income each month. If $1,000 more is invested at 9% than at 10% per year, how much was invested at each percent? There were 12 months in that year. \n" ); document.write( "
Algebra.Com's Answer #57487 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
John now has two investments that produce a $150 income each month. If $1,000 more is invested at 9% than at 10% per year, how much was invested at each percent?
\n" ); document.write( "---------
\n" ); document.write( "Amt invested at 9% = x; amt of monthly interest on this is (0.09/12) x dollars
\n" ); document.write( "-------
\n" ); document.write( "Amt invested at 10% = x+1000 ; amt of monthly int. on this is (0.10/12)(1000+x)
\n" ); document.write( "--------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "int + int = 150 dollars
\n" ); document.write( "0.0075x + 8.333 + 0.008333x=150
\n" ); document.write( "0.0158333x=141.667
\n" ); document.write( "x=$8947.41(amt. invested at 9%)
\n" ); document.write( "10000-8947.41=$1052.59 (amt. invested at 10%)
\n" ); document.write( "===========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
\n" );