document.write( "Question 942828: Find the equation of the SMALLEST circle tangent to the line
\n" ); document.write( "\"+x%2Bsqrt%28+3+%29y-2sqrt%28+3+%29+=+0+\"
\n" ); document.write( "and the coordinate axes. \r
\n" ); document.write( "\n" ); document.write( "Please help me solve this problem. Best regards!
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Algebra.Com's Answer #574861 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Smallest? There's only one solution.
\n" ); document.write( "Use the x and y intercepts.
\n" ); document.write( "They form a right triangle with a circle inscribed in that right triangle.
\n" ); document.write( "x-intercept : \"y=0\"
\n" ); document.write( "\"x-2sqrt%283%29=0\"
\n" ); document.write( "\"x=2sqrt%283%29\"
\n" ); document.write( "y-intercept : \"x=0\"
\n" ); document.write( "\"sqrt%283%29y-2sqrt%283%29=0\"
\n" ); document.write( "\"y=2\"
\n" ); document.write( "So you have a right triangle triangle with one leg, \"2sqrt%283%29\", and another leg, \"2\".
\n" ); document.write( "Find the hypotenuse using the Pythagorean theorem,
\n" ); document.write( "\"%282sqrt%283%29%29%5E2%2B2%5E2=H%5E2\"
\n" ); document.write( "\"12%2B4=H%5E2\"
\n" ); document.write( "\"H%5E2=16\"
\n" ); document.write( "\"H=4\"
\n" ); document.write( "For an inscribed circle in a right triangle,
\n" ); document.write( "\"R=%28A%2BB-H%29%2F2\"
\n" ); document.write( "\"R=%282sqrt%283%29%2B2-4%29%2F2\"
\n" ); document.write( "\"R=sqrt%283%29%2B1-2\"
\n" ); document.write( "\"R=sqrt%283%29-1\"
\n" ); document.write( "So the equation of the circle is,
\n" ); document.write( "\"%28x-%28sqrt%283%29-1%29%29%5E2%2B%28y-%28sqrt%283%29-1%29%29%5E2=%28sqrt%283%29-1%29%5E2\"
\n" ); document.write( "\"%28x-sqrt%283%29%2B1%29%5E2%2B%28y-sqrt%283%29%2B1%29%5E2=4-2sqrt%283%29\"
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