document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=942885>Question 942885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave towns <BR>\n" );
document.write( "480<BR>\n" );
document.write( " kilometers apart at the same time and travel toward each other. One car's rate is <BR>\n" );
document.write( "14<BR>\n" );
document.write( " kilometers per hour less than the other's. If they meet in <BR>\n" );
document.write( "3<BR>\n" );
document.write( " hours, what is the rate of the slower car? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574850 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two cars leave towns 480 kilometers apart at the same time and travel toward each other. One car'srate is 14 kilometers per hour less than the other's. If they meet in 3 hours, what is the rate of the slower car?<BR>\n" );
document.write( "..<BR>\n" );
document.write( "let x=rate of slower car<BR>\n" );
document.write( "x+14=rate of faster car<BR>\n" );
document.write( "Both cars are traveling toward each other at a rate=x+(14+x)=2x+14<BR>\n" );
document.write( "travel time*rate=distance<BR>\n" );
document.write( "3(2x+14)=480<BR>\n" );
document.write( "6x+42=480<BR>\n" );
document.write( "6x=452<BR>\n" );
document.write( "x=73<BR>\n" );
document.write( "what is the rate of the slower car? 73 km/hr </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );