document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=942880>Question 942880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Peter is 3 times as old as joseph.in 6 years time joseph's age will be 1/2 of peter's age. Find peter's age in 4 years time </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574832 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574832\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Peter's age; J=Joseph's age<BR>\n" );
document.write( "P=3J 2(J+6)=P+6<BR>\n" );
document.write( "3J=2(J+6)-6<BR>\n" );
document.write( "3J=2J+12-6<BR>\n" );
document.write( "3J=2J+6 subtract 2J from each side<BR>\n" );
document.write( "3J-2J=2J+6-2J<BR>\n" );
document.write( "J=6 Joseph is 6<BR>\n" );
document.write( "P=3J=3(6)=18 Peter is 18<BR>\n" );
document.write( "In 4 years Peter will be 22 years old<BR>\n" );
document.write( "CHECK <BR>\n" );
document.write( "in 6 years Joseph's age will be 1/2 Peter's age<BR>\n" );
document.write( "J+6=1/2(P+6)<BR>\n" );
document.write( "6+6=1/2(18+6)<BR>\n" );
document.write( "12=1/2(24)<BR>\n" );
document.write( "12=12 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );