document.write( "Question 942763: A man has a daughter and son .
\n" );
document.write( "The son is 3 years older than the daughter . In one year the man will be 6 times as old as the daughter is now. In 10 years,the man will be fourteen years older than the combined ages of his children at that time . What is the man present age?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #574812 by Merciful(5)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the daughter's present age \n" ); document.write( "The Son's present age is (x + 3) \n" ); document.write( "In one year the man will be 6x \n" ); document.write( "In 10 years the man will be (x + 10) (x + 13) + 14 \n" ); document.write( "From this we can say the man's present age is 6x-1 \n" ); document.write( "And also in 10 years the man will be 6x + 9 \n" ); document.write( "So:::(x + 10) (x + 13) + 14=6x + 9 \n" ); document.write( "4x=28 \n" ); document.write( "x=7 \n" ); document.write( "The man's present age = 6x-1 \n" ); document.write( "=6(7)-1 \n" ); document.write( "=41 \n" ); document.write( " |