document.write( "Question 942763: A man has a daughter and son .
\n" ); document.write( "The son is 3 years older than the daughter . In one year the man will be 6 times as old as the daughter is now. In 10 years,the man will be fourteen years older than the combined ages of his children at that time . What is the man present age?
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Algebra.Com's Answer #574812 by Merciful(5)\"\" \"About 
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Let x be the daughter's present age
\n" ); document.write( "The Son's present age is (x + 3)
\n" ); document.write( "In one year the man will be 6x
\n" ); document.write( "In 10 years the man will be (x + 10) (x + 13) + 14
\n" ); document.write( "From this we can say the man's present age is 6x-1
\n" ); document.write( "And also in 10 years the man will be 6x + 9
\n" ); document.write( "So:::(x + 10) (x + 13) + 14=6x + 9
\n" ); document.write( "4x=28
\n" ); document.write( "x=7
\n" ); document.write( "The man's present age = 6x-1
\n" ); document.write( "=6(7)-1
\n" ); document.write( "=41
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