document.write( "Question 942809: Suppose the measures of the two legs of a right triangle differ by 2 inches and that the hypotenuse is 2 inches longer than the longer leg. Find the measures of the three sides. \n" ); document.write( "

Algebra.Com's Answer #574763 by Fombitz(32388) $\"\"$ $\"About$

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So the legs would be $\"x\"$ and $\"x-2\"$ and the hypotenuse would be $\"x%2B2\"$ .
\n" ); document.write( "Use the Pythagorean theorem,
\n" ); document.write( " $\"%28x%2B2%29%5E2=x%5E2%2B%28x-2%29%5E2\"$
\n" ); document.write( " $\"x%5E2%2B4x%2B4=x%5E2%2Bx%5E2-4x%2B4\"$
\n" ); document.write( " $\"x%5E2%2B4x%2B4=2x%5E2-4x%2B4\"$
\n" ); document.write( " $\"x%5E2-8x=0\"$
\n" ); document.write( " $\"x%28x-8%29=0\"$
\n" ); document.write( "Only non-zero solutions make sense here,
\n" ); document.write( " $\"x-8=0\"$
\n" ); document.write( " $\"x=8\"$
\n" ); document.write( "So the lengths are 6,8, and 10.
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