document.write( "Question 942795: 243;81;27;... please explain the sequence \n" ); document.write( "

Algebra.Com's Answer #574749 by MathLover1(20855) $\"\"$ $\"About$

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to find each term, we divide by $\"3\"$ , a common ratio, from the previous term\r
\n" ); document.write( "\n" ); document.write( " $\"243%2F3=81\"$
\n" ); document.write( " $\"81%2F3=27\"$ \r
\n" ); document.write( "\n" ); document.write( "so, next would be
\n" ); document.write( " $\"27%2F3=9\"$
\n" ); document.write( " $\"9%2F3=3\"$
\n" ); document.write( " $\"3%2F3=1\"$
\n" ); document.write( " $\"1%2F3=1%2F3\"$ and so on\r
\n" ); document.write( "\n" ); document.write( "we can model it $\"243\"$ , $\"81\"$ , $\"27\"$ , $\"+9\"$ , $\"3\"$ , $\"1\"$ ... with the exponential function below:\r
\n" ); document.write( "\n" ); document.write( " $\"a%5Bn%5D=3%5E%28-n%2B+6%29+\"$ where $\"n\"$ = $\"1\"$ , $\"+2\"$ , $\"3\"$ , $\"4\"$ ...\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "When $\"n+=+1\"$ , which represents the first term, we get
\n" ); document.write( " $\"a%5B1%5D=+3%5E%28-1%2B+6%29+=+3%5E5+=+243\"$ \r
\n" ); document.write( "\n" ); document.write( "When $\"n+=+2\"$ , which represents the second term, we get \r
\n" ); document.write( "\n" ); document.write( " $\"a%5B2%5D=3%5E%28-2%2B+6%29+=+3%5E4+=+81\"$ \r
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