document.write( "Question 942740: Wanda started walking along a path 27 seconds before Dave. Wanda walked at a constant rate of 3 feet per second. Dave walked along the same path at a constant rate of 4.5 feet per second. How long after Dave starts walking will he catch up with Wanda ? Pls any one can help me to solve this problem thanks \n" ); document.write( "
Algebra.Com's Answer #574727 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Wanda started walking along a path 27 seconds before Dave. Wanda walked at a constant rate of 3 feet per second. Dave walked along the same path at a constant rate of 4.5 feet per second. How long after Dave starts walking will he catch up with Wanda ?
\n" ); document.write( "***
\n" ); document.write( "let x=travel time of Dave
\n" ); document.write( "x+27=travel time of Wanda
\n" ); document.write( "speed*travel time=distance (same for both Wanda and dave)
\n" ); document.write( "..
\n" ); document.write( "4.5x=3(x+27)
\n" ); document.write( "4.5x=3x+81
\n" ); document.write( "1.5x=81
\n" ); document.write( "x=54
\n" ); document.write( "How long after Dave starts walking will he catch up with Wanda ? 54 sec
\n" ); document.write( "
\n" );