document.write( "Question 942720: Maureen can run at a rate that is 2 miles per hour faster than her friend Hector's rate. While training for a mini marathon, Maureen gives Hector a half-hour head start and then begins chasing Hector on the same route. If Maureen passes Hector 12 miles from the starting point, how fast is each running?
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Algebra.Com's Answer #574721 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Maureen can run at a rate that is 2 miles per hour faster than her friend Hector's rate. While training for a mini marathon, Maureen gives Hector a half-hour head start and then begins chasing Hector on the same route. If Maureen passes Hector 12 miles from the starting point, how fast is each running?
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\n" ); document.write( "Let Maureen’s speed be S
\n" ); document.write( "Then Hector’s is: S - 2
\n" ); document.write( "Since she passed Hector 12 miles from the starting point and with Hector getting a ˝ hr head start,
\n" ); document.write( "we get: \"12%2FS+-+1%2F2+=+12%2F%28S+-+2%29\"
\n" ); document.write( "12(2)(S – 2) – S(S – 2) = 12(2S) ---- Multiplying by LCD, 2S(S – 2)
\n" ); document.write( "\"24S+-+48+-+S%5E2+%2B+2S+=+24S\"
\n" ); document.write( "\"26S+-+48+-+S%5E2+=+24S\"
\n" ); document.write( "\"S%5E2+%2B+24S+-+26S+%2B+48+=+0\"
\n" ); document.write( "\"S%5E2+-+2S+%2B+48+=+0\"
\n" ); document.write( "(S - 8)(S + 6) = 0
\n" ); document.write( "S, or Maureen’s speed = \"highlight_green%288%29\" mph OR S = - 6 (ignore)
\n" ); document.write( "Hector’s speed: 8 – 2, or \"highlight_green%286%29\" mph \n" ); document.write( "
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