document.write( "Question 942700: find the roots for: (2s-5)(3s+7)
\n" ); document.write( "then, expand the factors into a quadratic equation
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Algebra.Com's Answer #574702 by TimothyLamb(4379)\"\" \"About 
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(2s-5)(3s+7)
\n" ); document.write( "---
\n" ); document.write( "root 1:
\n" ); document.write( "2s-5 = 0
\n" ); document.write( "2s = 5
\n" ); document.write( "s = 5/2
\n" ); document.write( "s = 2.5
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\n" ); document.write( "root 2:
\n" ); document.write( "3s+7 = 0
\n" ); document.write( "3s = -7
\n" ); document.write( "s = -7/3
\n" ); document.write( "s = -2.33333333
\n" ); document.write( "---
\n" ); document.write( "expand the quadratic:
\n" ); document.write( "y = (2s-5)(3s+7)
\n" ); document.write( "y = 6ss - s - 35
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\n" ); document.write( "check by finding the roots again, but using a different method:
\n" ); document.write( "6ss - s - 35 = 0
\n" ); document.write( "---
\n" ); document.write( "the above quadratic equation is in standard form, with a=6, b=-1 and c=-35
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\n" ); document.write( "to solve the quadratic equation, by using the quadratic formula, copy and paste this:
\n" ); document.write( "6 -1 -35
\n" ); document.write( "into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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\n" ); document.write( "the quadratic has two real roots at:
\n" ); document.write( "---
\n" ); document.write( "s = 2.5
\n" ); document.write( "s = -2.33333333
\n" ); document.write( "---
\n" ); document.write( "Free algebra tutoring live chat:
\n" ); document.write( "https://sooeet.com/chat.php?gn=algebra
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\n" ); document.write( "Solve and graph linear equations:
\n" ); document.write( "https://sooeet.com/math/linear-equation-solver.php
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\n" ); document.write( "Solve quadratic equations with quadratic formula:
\n" ); document.write( "https://sooeet.com/math/quadratic-formula-solver.php
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\n" ); document.write( "Solve systems of linear equations up to 6-equations 6-variables:
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