document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=942600>Question 942600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is one less than four times another. If their sum is decreased by three, the result is sixteen. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574640 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one number is x; another is 4x-1 Sum=19<BR>\n" );
document.write( "x+4x-1=19<BR>\n" );
document.write( "5x-1=19 add 1 to each side<BR>\n" );
document.write( "5x=20 divide each side by 5<BR>\n" );
document.write( "5x/5=20/5<BR>\n" );
document.write( "X=4 One Number<BR>\n" );
document.write( "4(4)-1=15 The other number<BR>\n" );
document.write( "CHECK <BR>\n" );
document.write( "Sum reduced by 3 is sixteen<BR>\n" );
document.write( "(4+15)-3=16<BR>\n" );
document.write( "19-3=16<BR>\n" );
document.write( "16=16 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );