document.write( "Question 942592: how can i find 5 consecutive integers such that the sum of the 4th and the 5th is 56 more than triple the 1st? \n" ); document.write( "
Algebra.Com's Answer #574639 by macston(5194)![]() ![]() You can put this solution on YOUR website! first=x, second =x+1, third=x+2, fourth=x+3, fifth=x+4 \n" ); document.write( "3x+56=x+3+x+4 \n" ); document.write( "3x+56=2x+7 subtract 2x from each side \n" ); document.write( "3x-2x+56=2x+7-2x \n" ); document.write( "x+56=7 subtract 56 from each side \n" ); document.write( "x+56-56=7-56 \n" ); document.write( "x=-49 first= -49 \n" ); document.write( "fourth=x+3=-46 \n" ); document.write( "fifth=x+4=-45 \n" ); document.write( "CHECK: Sum offourth and fifth is 56 more than triple first \n" ); document.write( "-45+-46=3(-49)+56 \n" ); document.write( "-91=(-147)+56 \n" ); document.write( "-91=-91 \n" ); document.write( " |