document.write( "Question 942578: The question is \"How many ounces of a silver alloy that costs $11 per ounce must be mixed with 9 ounces of a silver alloy that costs $8 per ounce to make an alloy that costs $9 per ounce?\"\r
\n" ); document.write( "\n" ); document.write( "The problem I have is understanding what formula to use and exactly how to you solve it. I would appreciate the help thank you!
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Algebra.Com's Answer #574637 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = ounces of $11/ounce alloy to be used
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\n" ); document.write( "\"+11x+%2B+8%2A9+=+9%2A%28+x+%2B+9+%29+\"
\n" ); document.write( "\"+11x+%2B+72+=+9x+%2B+81+\"
\n" ); document.write( "\"+2x+=+9+\"
\n" ); document.write( "\"+x+=+4.5+\"
\n" ); document.write( "4.5 ounces of $11/ounce alloy should be used
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\n" ); document.write( "check:
\n" ); document.write( "\"+11x+%2B+8%2A9+=+9%2A%28+x+%2B+9+%29+\"
\n" ); document.write( "\"+11%2A4.5+%2B+8%2A9+=+9%2A%28+4.5+%2B+9+%29+\"
\n" ); document.write( "\"+49.5+%2B+72+=+9%2A13.5+\"
\n" ); document.write( "\"+121.5++=+121.5+\"
\n" ); document.write( "OK
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