document.write( "Question 942564: The perimeter of a rectangle is 30m and the length is 10m more than the width.find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #574616 by macston(5194)\"\" \"About 
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P=2(L+W)=30 m; L=W+10
\n" ); document.write( "30 m=2(W+10+W)
\n" ); document.write( "30 m=4W+20 subtract 20 from each side
\n" ); document.write( "30m-20m=4W+20m-20m
\n" ); document.write( "10m=4W Divide each side by 4
\n" ); document.write( "10 m/4=4W/4
\n" ); document.write( "2.5 m=W width=2.5 m
\n" ); document.write( "L=W+10=12.5 Length = 12.5 m
\n" ); document.write( "CHECK
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "30 m=2(12.5m+2.5m)
\n" ); document.write( "30 m=2(15m)
\n" ); document.write( "30 m=30 m
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