document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=942514>Question 942514</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a boat moves at a rate of 10mph in still water. if the river's current flows at a rate of 3mph, how long does it take the boat to travel 32 miles upstream? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574613 by </B><A HREF=/tutors/aboutme.mpl?userid=eternalblaze21><B>eternalblaze21(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=eternalblaze21><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574613\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> B is rate of boat=10 mph<BR>\n" );
document.write( "W is rate of river/water=3 mph<BR>\n" );
document.write( "(B-W)Tu=D <--equation for traveling upstream<BR>\n" );
document.write( "(10-3)Tu=32<BR>\n" );
document.write( "7Tu=32<BR>\n" );
document.write( "Tu=32/7 hrs or 4.6 hrs\r<BR>\n" );
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document.write( "Additional notes:<BR>\n" );
document.write( "If you were traveling downstream, your equation would look like this: (B+W)Td=D </SPAN>\n" );
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