document.write( "Question 942490: Juan scored 10 points higher on his midterm and 26 points higher on his final than he did on his first exam. If his mean (average) score was 45, what was his score on the first exam?
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Algebra.Com's Answer #574563 by macston(5194) $\"\"$ $\"About$

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S= score on first exam
\n" ); document.write( "S+10= score on mid-term
\n" ); document.write( "S+26= score on final
\n" ); document.write( "A=Mean(Average)=45
\n" ); document.write( "Mean(average)=A= $\"%28first_exam%2Bmid-term%2Bfinal%29%2F3\"$
\n" ); document.write( " $\"A=%28S%2B%28S%2B10%29%2B%28S%2B26%29%29%2F3\"$
\n" ); document.write( " $\"A=%283S%2B36%29%2F3\"$
\n" ); document.write( " $\"A=S%2B12\"$ Substitute A(given)
\n" ); document.write( "45=S+12 Subtract 12 from each side
\n" ); document.write( "45-12=S+12-12
\n" ); document.write( "33=S The score on the first exam was 33
\n" ); document.write( "S+10=43 The score on the midterm was 43
\n" ); document.write( "S+26=59 The score on the final was 59
\n" ); document.write( " $\"%2833%2B43%2B59%29%2F3=135%2F3=45\"$ , Juan's average for the three exams\r
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