document.write( "Question 942488: Mary can jog, on average, 2 miles per hour faster than her husband, James. James can jog 6.6 miles in the same amount of time it takes Mary to jog 9 miles. Mary can jog __________ miles per hour?
\n" ); document.write( "Another word problem I can not comprehend \n" ); document.write( "
Algebra.Com's Answer #574553 by macston(5194)\"\" \"About 
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M=Mary's rate J=Jame's rate
\n" ); document.write( "M=J+2 Mary is 2mph faster than James
\n" ); document.write( "6.6 mi/J=9 mi/M James runs 6.6 miles in the time it takes Mary to run 9 miles
\n" ); document.write( "Substitute M=J+2 in the second equation to solve for J
\n" ); document.write( "6.6/J=9/J+2 Multiply each side by J
\n" ); document.write( "6.6J/J=9J/J+2
\n" ); document.write( "6.6=9J/J+2 Multiply each side by J+2
\n" ); document.write( "6.6(J+2)=9J(J+2)/(J+2)
\n" ); document.write( "6.6J+13.2=9J subtract 6.6J from each side
\n" ); document.write( "6.6J+13.2-6.6J=9J-6.6J
\n" ); document.write( "13.2=2.4J Divide each side by 2.4
\n" ); document.write( "13.2/2.4=2.4J/2.4
\n" ); document.write( "5.5=J So James can run at 5.5 mph and Mary runs at 7.5 mph (J+2)
\n" ); document.write( "CHECK
\n" ); document.write( "James runs 6.6 miles in 6.6 mi/5.5 mph=1.2 hrs
\n" ); document.write( "Mary runs 9 miles in 9mi/7.5 mph=1.2 hrs \n" ); document.write( "
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