document.write( "Question 942477: Three years ago the average age of A and B was 18 years. While C joining them now, the average
\n" ); document.write( "becomes 22 years. How old (in years) is C now?
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Algebra.Com's Answer #574543 by macston(5194)\"\" \"About 
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If three years ago the average was 18, today the average is 21 so
\n" ); document.write( "(A+B)/2=21
\n" ); document.write( "A+B=42
\n" ); document.write( "with C the average is 22 so
\n" ); document.write( "(A+B+C)/3=22
\n" ); document.write( "A+B+C=66 Substitute A+B from above
\n" ); document.write( "(A+B)+C=66
\n" ); document.write( "42+C=66 subtract 42 from each side
\n" ); document.write( "C=24 so C is currently 24 years old
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