document.write( "Question 942447: in a rectangle the width is four more than one fifth of the length. The perimeter is 32 inches. Find the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #574533 by macston(5194)\"\" \"About 
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Length=L Width=W=1/5L+4
\n" ); document.write( "Perimeter=P=2(L+W)=32 in Substitute for W
\n" ); document.write( "2(L+(1/5L+4))=32 in
\n" ); document.write( "2L+2/5L+8=32 in subtract 8 from each side
\n" ); document.write( "2 2/5 L+8-8=32-8 in convert to decimal
\n" ); document.write( "2.4L=24 divide both sides by 2.4
\n" ); document.write( "2.4L/2.4=24/2.4 in
\n" ); document.write( "L=10
\n" ); document.write( "CHECK:
\n" ); document.write( "If L=10, W=1/5(10)+4=2+4=6
\n" ); document.write( "P=2(L+W)=32 in
\n" ); document.write( "P=2(10+6)=32 in
\n" ); document.write( "P=32in=32in \r
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