document.write( "Question 942447: in a rectangle the width is four more than one fifth of the length. The perimeter is 32 inches. Find the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #574533 by macston(5194)![]() ![]() You can put this solution on YOUR website! Length=L Width=W=1/5L+4 \n" ); document.write( "Perimeter=P=2(L+W)=32 in Substitute for W \n" ); document.write( "2(L+(1/5L+4))=32 in \n" ); document.write( "2L+2/5L+8=32 in subtract 8 from each side \n" ); document.write( "2 2/5 L+8-8=32-8 in convert to decimal \n" ); document.write( "2.4L=24 divide both sides by 2.4 \n" ); document.write( "2.4L/2.4=24/2.4 in \n" ); document.write( "L=10 \n" ); document.write( "CHECK: \n" ); document.write( "If L=10, W=1/5(10)+4=2+4=6 \n" ); document.write( "P=2(L+W)=32 in \n" ); document.write( "P=2(10+6)=32 in \n" ); document.write( "P=32in=32in \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |