document.write( "Question 942415: What is the actual volume of a swimming pool with dimensions 5 cm (width) 2 cm (length) and 4 cm (depth) each centimeter represents 3 feet on the actual structure \n" ); document.write( "
Algebra.Com's Answer #574527 by macston(5194)![]() ![]() You can put this solution on YOUR website! Width=W=5 cm(3 ft/cm)= 15 ft \n" ); document.write( "Length=L=2 cm(3 ft/cm)=6 ft \n" ); document.write( "Depth=D=4 cm(3 ft/cm)=12 ft \n" ); document.write( "Volume=V=L x W x D \n" ); document.write( "V=(6 ft)(15 ft)(12 ft)= 1080 cu ft \n" ); document.write( " |