document.write( "Question 942430: A fair coin is flipped 10 times. Find the probability of the occurrence of 5 or 6 heads. \n" ); document.write( "
Algebra.Com's Answer #574525 by mathmate(429)\"\" \"About 
You can put this solution on YOUR website!
Given:
\n" ); document.write( "A fair coin
\n" ); document.write( "Flipped 10 times
\n" ); document.write( "
\n" ); document.write( "This means that
\n" ); document.write( "1. probability of heads (success) is constant at p=0.5
\n" ); document.write( "2. \"flipping 10 times\" imply random and independent outcomes over the experiment
\n" ); document.write( "3. The number of trials (flip) is known.
\n" ); document.write( "4. Each trial is a Bernoulli experiment (one of two possible outcomes).
\n" ); document.write( "Under these conditions, the binomial distribution applies.
\n" ); document.write( "
\n" ); document.write( "The probability of r successes in n trials is given by:
\n" ); document.write( "\"P%28X=r%29+=+C%28n%2Cr%29%2A%28p%5Er%29%2A%28q%5E%28n-r%29%29\"
\n" ); document.write( "where C(n,r) is r combinations out of n objects = \"n%21%2F%28%28n-r%29%21r%21%29\"
\n" ); document.write( "and q=(1-p)
\n" ); document.write( "
\n" ); document.write( "Substituting values n=10, p=0.5, r=5 or 6, we get
\n" ); document.write( "\"P%28X=5%29+=+C%2810%2C5%29%2A%280.5%5E5%29%2A%28%281-0.5%29%5E%2810-5%29%29=0.246\"
\n" ); document.write( "\"P%28X=6%29+=+C%2810%2C6%29%2A%280.5%5E6%29%2A%28%281-0.5%29%5E%2810-6%29%29=0.205\"
\n" ); document.write( "
\n" ); document.write( "Probability of 5 or 6 heads is the sum of P(X=5) and P(X=6)
\n" ); document.write( "\"P%28X=5+or+X=6%29=0.246%2B0.205=0.451\"
\n" ); document.write( "
\n" ); document.write( "
\n" );