document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=942347>Question 942347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you do y=-5x+12<BR>\n" );
document.write( "                            y=1x-18 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574521 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you have 2 equations.<BR>\n" );
document.write( "y = -5x + 12<BR>\n" );
document.write( "y = 1x - 18<BR>\n" );
document.write( "subtract the first equation from the second equation to get:<BR>\n" );
document.write( "0 = 6x - 30<BR>\n" );
document.write( "add 30 to both sides to get 6x = 30<BR>\n" );
document.write( "solve for x to get x = 5<BR>\n" );
document.write( "that's your common solution to both equations.\r<BR>\n" );
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document.write( "y = -5x + 12 becomes y = -5(5) + 12 which becomes y = -25 + 12 which becomes y = -13.\r<BR>\n" );
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document.write( "y = x - 18 becomes y = 5 - 18 which becomes y = -13.\r<BR>\n" );
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document.write( "both equations give you y = -13 when x = 5.\r<BR>\n" );
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document.write( "you could also have simply set both equations equal to each other.\r<BR>\n" );
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document.write( "since y = -5x + 12 and y = x - 18, then by substution, you get -5x + 12 = x - 18\r<BR>\n" );
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document.write( "add 5x to both sides of this equation and add 18 to both sides of this equation to get 30 = 6x<BR>\n" );
document.write( "solve for x to get x = 5.\r<BR>\n" );
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document.write( "same answer either way.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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