document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=942364>Question 942364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a question on the way to find the sides of an isosceles right triangle with a hypotenuse that is radical 72. <BR>\n" );
document.write( "I solved the question <BR>\n" );
document.write( "\"Determine the perimeter of a square with a diagonal of radical 72 centimeters\"<BR>\n" );
document.write( "To find the perimeter I musty first find the length of the side of the square\r<BR>\n" );
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document.write( "Then I set up and equation and turn a segment the square into a triangle using the diagonal as the hypotenuse \r<BR>\n" );
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document.write( "I then simplified the equation\r<BR>\n" );
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document.write( "I divided by 2\r<BR>\n" );
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document.write( "And I found the square roots \r<BR>\n" );
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document.write( "I then found the perimeter by multiplying 4 by the value of x\r<BR>\n" );
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document.write( "P=26<BR>\n" );
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document.write( "Instructor comment: When you draw the diagonal through the square, you create a 45-45-90 triangle, where the hypotenuse is radical 72; then you can use those patterns to find the side length of the square to use to find the perimeter.\r<BR>\n" );
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document.write( "Please show me the correct way to solve it </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574515 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have a question on the way to find the sides of an isosceles right triangle with a hypotenuse that is radical 72. <BR>\n" );
document.write( "I solved the question <BR>\n" );
document.write( "\"Determine the perimeter of a square with a diagonal of radical 72 centimeters\"<BR>\n" );
document.write( "To find the perimeter I musty first find the length of the side of the square\r<BR>\n" );
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document.write( "Then I set up and equation and turn a segment the square into a triangle using the diagonal as the hypotenuse \r<BR>\n" );
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document.write( "I then simplified the equation\r<BR>\n" );
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document.write( "I divided by 2\r<BR>\n" );
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document.write( "And I found the square roots \r<BR>\n" );
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document.write( "I then found the perimeter by multiplying 4 by the value of x\r<BR>\n" );
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document.write( "P=26<BR>\n" );
document.write( " <BR>\n" );
document.write( "Instructor comment: When you draw the diagonal through the square, you create a 45-45-90 triangle, where the hypotenuse is radical 72; then you can use those patterns to find the side length of the square to use to find the perimeter.\r<BR>\n" );
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document.write( "Please show me the correct way to solve it<BR>\n" );
document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\"><BR>\n" );
document.write( "You need to find one of the sides of the square before you can determine the perimeter of the square. <BR>\n" );
document.write( "Since it’s a square, each side can be named, S<BR>\n" );
document.write( "Since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2+%2B+b%5E2+=+c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2+%2B+b%5E2+=+c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, then we’d have: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%5E2+%2B+S%5E2+=+%28sqrt%2872%29%29%5E2 ALIGN=MIDDLE  ALT=\"S%5E2+%2B+S%5E2+=+%28sqrt%2872%29%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and you could solve for S. Then you’d be able to find the perimeter.\r<BR>\n" );
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document.write( "However, what the professor is saying is that when a 45-45-90 special triangle exists<BR>\n" );
document.write( "(and this does occur in a square), and one of the sides is named S, the hypotenuse (the diagonal in this case)<BR>\n" );
document.write( "is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S+%2A+sqrt%282%29 ALIGN=MIDDLE  ALT=\"S+%2A+sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Now, since it’s given that the diagonal or hypotenuse is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2872%29 ALIGN=MIDDLE  ALT=\"sqrt%2872%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, it then follows that: <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S+%2A+sqrt%282%29+=+sqrt%2872%29 ALIGN=MIDDLE  ALT=\"S+%2A+sqrt%282%29+=+sqrt%2872%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28S+%2A+sqrt%282%29%29%5E2+=+%28sqrt%2872%29%29%5E2 ALIGN=MIDDLE  ALT=\"%28S+%2A+sqrt%282%29%29%5E2+=+%28sqrt%2872%29%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > -------- Squaring both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%5E2+%2A+2+=+72 ALIGN=MIDDLE  ALT=\"S%5E2+%2A+2+=+72\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2S%5E2+=+72 ALIGN=MIDDLE  ALT=\"2S%5E2+=+72\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%5E2+=+72%2F2 ALIGN=MIDDLE  ALT=\"S%5E2+=+72%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%5E2+=+36 ALIGN=MIDDLE  ALT=\"S%5E2+=+36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "S = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2836%29 ALIGN=MIDDLE  ALT=\"sqrt%2836%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or 6\r<BR>\n" );
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document.write( "With S or one side being 6, the perimeter is: 4(6), or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2824%29 ALIGN=MIDDLE  ALT=\"highlight_green%2824%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm </SPAN>\n" );
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