document.write( "Question 942359: how man gallons of a 20% acid solution must be mixed with 6 gallon of a 30% acid solution to make a 22% solution. \n" ); document.write( "

Algebra.Com's Answer #574473 by lwsshak3(11628) $\"\"$ $\"About$

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how many gallons of a 20% acid solution must be mixed with 6 gallon of a 30% acid solution to make a 22% solution.
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\n" ); document.write( "let x=amt of 20% solution must be mixed
\n" ); document.write( "30%*6+20%x=22%(6+x)
\n" ); document.write( "1.8+.2x=1.32+.22x
\n" ); document.write( ".02x=0.48
\n" ); document.write( "x=24
\n" ); document.write( "how many gallons of a 20% acid solution must be mixed? 24 \n" ); document.write( "

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