document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=942333>Question 942333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two planes are 1410 mi apart and are traveling toward each other. One plane is traveling 120 mph faster than the other plane. The planes pass each other in 1.5 h. Find the speed of each plane.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574462 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two planes are 1410 mi apart and are traveling toward each other. One plane is traveling 120 mph faster than the other plane. The planes pass each other in 1.5 h. Find the speed of each plane. <BR>\n" );
document.write( "***<BR>\n" );
document.write( "x=speed of slower plane<BR>\n" );
document.write( "x+120=speed of faster plane<BR>\n" );
document.write( "travel time*speed=distance(same for both planes)<BR>\n" );
document.write( "1.5x+1.5(x+120)=1410<BR>\n" );
document.write( "1.5(2x+120)=1410<BR>\n" );
document.write( "3x+180=1410<BR>\n" );
document.write( "3x=1230<BR>\n" );
document.write( "x=410<BR>\n" );
document.write( "x+120=530<BR>\n" );
document.write( "speed of slower plane=410 mph<BR>\n" );
document.write( "speed of faster plane=530 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );