document.write( "Question 80081: In the equation:
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Algebra.Com's Answer #57440 by bucky(2189)\"\" \"About 
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False
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\n" ); document.write( "If x and y vary directly, then as one of them increases, the other must increase also.
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\n" ); document.write( "This means that x cannot be in the denominator unless y is also in a denominator.
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\n" ); document.write( "Think about this. Let's say that x = 1. Then the given equation becomes:
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\n" ); document.write( "y = 2/x = 2/1 = 2
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\n" ); document.write( "Now let's increase x by saying that x is going to be 2. If y varied directly as x then
\n" ); document.write( "because we increased x, y should also increase. But when we substitute 2 for x, the
\n" ); document.write( "equation becomes:
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\n" ); document.write( "y = 2/x = 2/2 = 1
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\n" ); document.write( "Notice that when x went from 1 to 2, the value of y went down from 2 to 1. So y does not
\n" ); document.write( "vary directly as x. It varies inversely ... the bigger x gets the smaller y gets.
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\n" ); document.write( "Hope this helps you to understand the problem a little better. And sometimes it helps
\n" ); document.write( "just to plug numbers in and see what happens to one of the variables if you increase
\n" ); document.write( "(or decrease) the other one ... just as we did above.
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