document.write( "Question 80081: In the equation:
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document.write( "y=2/x
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document.write( "x and y vary directly.
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document.write( " True
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document.write( " False
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Algebra.Com's Answer #57440 by bucky(2189) ![]() You can put this solution on YOUR website! False \n" ); document.write( ". \n" ); document.write( "If x and y vary directly, then as one of them increases, the other must increase also. \n" ); document.write( "(or as one of them decreases, the other must decrease also). \n" ); document.write( ". \n" ); document.write( "This means that x cannot be in the denominator unless y is also in a denominator. \n" ); document.write( ". \n" ); document.write( "Think about this. Let's say that x = 1. Then the given equation becomes: \n" ); document.write( ". \n" ); document.write( "y = 2/x = 2/1 = 2 \n" ); document.write( ". \n" ); document.write( "Now let's increase x by saying that x is going to be 2. If y varied directly as x then \n" ); document.write( "because we increased x, y should also increase. But when we substitute 2 for x, the \n" ); document.write( "equation becomes: \n" ); document.write( ". \n" ); document.write( "y = 2/x = 2/2 = 1 \n" ); document.write( ". \n" ); document.write( "Notice that when x went from 1 to 2, the value of y went down from 2 to 1. So y does not \n" ); document.write( "vary directly as x. It varies inversely ... the bigger x gets the smaller y gets. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem a little better. And sometimes it helps \n" ); document.write( "just to plug numbers in and see what happens to one of the variables if you increase \n" ); document.write( "(or decrease) the other one ... just as we did above. \n" ); document.write( " |