document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=942243>Question 942243</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A local hamburger shop sold a combined total of <BR>\n" );
document.write( "491<BR>\n" );
document.write( " hamburgers and cheeseburgers on Saturday. There were <BR>\n" );
document.write( "59<BR>\n" );
document.write( " fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Saturday? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574391 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> H=no of hamburgers C=no of cheeseburgers<BR>\n" );
document.write( "C=H-59<BR>\n" );
document.write( "H+C=491 substitute above for C and solve for H<BR>\n" );
document.write( "H+(H-59)=491<BR>\n" );
document.write( "2H-59=491 Add 59 to each side<BR>\n" );
document.write( "2H-59+59=491+59<BR>\n" );
document.write( "2H=550 Divide both sides by 2<BR>\n" );
document.write( "2H/2=550/2<BR>\n" );
document.write( "H=275 Number of hamburgers = 275<BR>\n" );
document.write( "C=275-59=216 Number of cheeseburgers=216<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "H+C=491<BR>\n" );
document.write( "275+216=491<BR>\n" );
document.write( "491=491 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );