document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=941736>Question 941736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 3 less than half the length. Find the length if the perimeter is 54. <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574324 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length=L Width=W=1/2L-3<BR>\n" );
document.write( "P=2(L+W)Substitute above for W<BR>\n" );
document.write( "54 m=2(L+1/2L-3)<BR>\n" );
document.write( "54 m=2(1.5L-3)<BR>\n" );
document.write( "54 m=3L-6 add 6 to each side<BR>\n" );
document.write( "54+6 m=3L-6+6<BR>\n" );
document.write( "60=3L divide each side by 3<BR>\n" );
document.write( "60/3 m=3L/3<BR>\n" );
document.write( "20 m=L ANSWER length=20 meters<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "W=1/2L-3=1/2(20)-3=10-3=7 m<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "54 m=2(20m + 7m)<BR>\n" );
document.write( "54m=2(27m)<BR>\n" );
document.write( "54m=54m<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );