document.write( "Question 942184: What quantity of a 50% acid solution must be mixed with a 20% solution to produce 600 mL of a 40% solution
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Algebra.Com's Answer #574320 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! What quantity of a 50% acid solution must be mixed with a 20% solution to produce 600 mL of a 40% solution \n" ); document.write( " ------ \n" ); document.write( "Equation:: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.50x + 0.20(600-x) = 0.40*600 \n" ); document.write( "---------------------- \n" ); document.write( "50x + 20*600 - 20x = 40*600 \n" ); document.write( "30x = 20*600 \n" ); document.write( "x = 20*20 \n" ); document.write( "x = 400 mL (amt. of 50% solution needed) \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( " |