document.write( "Question 942184: What quantity of a 50% acid solution must be mixed with a 20% solution to produce 600 mL of a 40% solution
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Algebra.Com's Answer #574320 by stanbon(75887)\"\" \"About 
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What quantity of a 50% acid solution must be mixed with a 20% solution to produce 600 mL of a 40% solution
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\n" ); document.write( "Equation::
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.50x + 0.20(600-x) = 0.40*600
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\n" ); document.write( "50x + 20*600 - 20x = 40*600
\n" ); document.write( "30x = 20*600
\n" ); document.write( "x = 20*20
\n" ); document.write( "x = 400 mL (amt. of 50% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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