document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10955>Question 10955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 10 mm. longer than its width and its perimeter is 52 mm. Find the dimensions of the rectangle.\r<BR>\n" );
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document.write( "Thanks a lot if anyone could help me solve this problem.\r<BR>\n" );
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document.write( "Beth </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5743 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello Beth<BR>\n" );
document.write( "Let the width = W<BR>\n" );
document.write( "Then length = W+10<BR>\n" );
document.write( "Perimeter of a rectanlge = 2x(l+w)= 52\r<BR>\n" );
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document.write( "52= 2(w+w+10) \r<BR>\n" );
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document.write( "Dividing by 2 throughout<BR>\n" );
document.write( "26 = 2w+10<BR>\n" );
document.write( "Subtracting 10 from both sides<BR>\n" );
document.write( "16 = 2w<BR>\n" );
document.write( "Again dividing by 2 throughout\r<BR>\n" );
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document.write( "8 = w<BR>\n" );
document.write( "which means L = 8+10 = 18 </SPAN>\n" );
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