document.write( "Question 942123: 2. Automotive engineers refer to the time rate of change of acceleration as the “ jerk.” Assume an object moves in one dimension such that its jerk J is constant.\r
\n" ); document.write( "\n" ); document.write( "(a) Determine expressions for its acceleration a(t), velocity v(t), and position x(t), given that its initial acceleration, velocity, and position are a0, v0, and x0, respectively.\r
\n" ); document.write( "\n" ); document.write( "(b) Show that \"+a2+=+a02+%2B+2+J+%28v+-+v0%29+\"\r
\n" ); document.write( "\n" ); document.write( "NOTE: Finding the equations for motion with constant jerk is very similar to finding the equations for constant acceleration. Jerk is the derivative of acceleration ( J = da/dt ), and you already know that v = dx/dt and a = dv/dt. Just integrate in part (a) and rearrange in part (b) like we did in class when we derived the expressions for constant acceleration.
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Algebra.Com's Answer #574271 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
a) \r
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\n" ); document.write( "\n" ); document.write( "b) You should specify what a_2 is. Not clear to us.
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