document.write( "Question 942085: If you travel from your home to the store for 12 minutes at 20 mph then you traveled back home along the same path downhill at 60 mph. What is the average speed to the store and back? \n" ); document.write( "
Algebra.Com's Answer #574254 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
average speed is always:
\n" ); document.write( "( total distance ) / ( total time )
\n" ); document.write( "\"+d+=+20%2A%28+12%2F60+%29+\"
\n" ); document.write( "\"+d+=+4+\" mi
\n" ); document.write( "\"+t%5B1%5D=+3%2F15\"
\n" ); document.write( "----------------
\n" ); document.write( "\"+d+=+60t+\"
\n" ); document.write( "\"+4+=+60t+\"
\n" ); document.write( "\"+t%5B2%5D+=+4%2F60+\"
\n" ); document.write( "\"+t%5B2%5D+=+1%2F15+\" hrs
\n" ); document.write( "-------------------
\n" ); document.write( "Ave speed =\"++2%2A4+%2F+%28+3%2F15+%2B+1%2F15+%29+\"
\n" ); document.write( "Ave speed= \"+8+%2F+%284%2F15%29+\"
\n" ); document.write( "Ave speed = \"+%28+15%2F4+%29%2A8+\"
\n" ); document.write( "Ave speed = \"+30+\"
\n" ); document.write( "Average speed to the store and back is 30 mi/hr\r
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