document.write( "Question 942063: Mrs. Jones is 3 times as old as her son. Ten years ago she was 5 times as old as her son was then. Find each of their ages. \n" ); document.write( "
Algebra.Com's Answer #574228 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Mrs. Jones is 3 times as old as her son. Ten years ago she was 5 times as old as her son was then. Find each of their ages. \n" ); document.write( "------------ \n" ); document.write( "j = her age \n" ); document.write( "s = son's age \n" ); document.write( "--- \n" ); document.write( "j = 3s \n" ); document.write( "j-10 = 5*(s-10) \n" ); document.write( "Sub for j \n" ); document.write( "3s-10 = 5s-50 \n" ); document.write( "etc \n" ); document.write( " \n" ); document.write( " |