document.write( "Question 941929: Solve using a system: Roy and Chuck are two miles apart riding toward each other on their bicycles. They will meet in 20 minutes. If Roy were to ride twice as fast and Chuck were to ride three times as fast, the could meet in 8 minutes. How fast is each boy riding? \n" ); document.write( "
Algebra.Com's Answer #574198 by josmiceli(19441) You can put this solution on YOUR website! In both cases, I can think of this as one \n" ); document.write( "of them ( either one ) standing still, and \n" ); document.write( "the other moving at the sum of their speeds \n" ); document.write( "Let \n" ); document.write( "Let \n" ); document.write( "--------------------------------------- \n" ); document.write( "1st case: \n" ); document.write( "(1) \n" ); document.write( "2nd case: \n" ); document.write( "(2) \n" ); document.write( "--------------------------- \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "------------------------- \n" ); document.write( "Multiply both sides of (1) by \n" ); document.write( "and subtract (1) from (2) \n" ); document.write( "(2) \n" ); document.write( "(1) \n" ); document.write( "---------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "--------------------- \n" ); document.write( "Both of them travel at 1 mi in 20 min \n" ); document.write( " \n" ); document.write( "Both travel at 3 mi/hr \n" ); document.write( "---------------------- \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "OK \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |