document.write( "Question 941945: Find the point on the x-axis that is equidistant from (-4,-3) and (-1,5). \n" ); document.write( "
Algebra.Com's Answer #574188 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Find the point on the x-axis that is equidistant from (-4,-3) and (-1,5)\r\n" );
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document.write( "Every point on the x-axis has its y-coordinate as 0.  So we label\r\n" );
document.write( "the point we are looking for (x,0).\r\n" );
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document.write( "Then we use the distance formula to set the distances from (x,0) to\r\n" );
document.write( "the two given points equal to each other:\r\n" );
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document.write( "\"sqrt%28%28x%5E%22%22-%28-1%29%29%5E2%2B%280-5%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28x%5E%22%22-%28-4%29%29%5E2%2B%280-%28-3%29%29%5E2%29\"\r\n" );
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document.write( "\"sqrt%28%28x%2B1%29%5E2%2B%28-5%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28x%2B4%29%5E2%2B%280%2B3%29%5E2%29\"\r\n" );
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document.write( "\"sqrt%28%28x%2B1%29%5E2%2B25%29\"\"%22%22=%22%22\"\"sqrt%28%28x%2B4%29%5E2%2B%283%29%5E2%29\"\r\n" );
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document.write( "\"sqrt%28%28x%2B1%29%5E2%2B25%29\"\"%22%22=%22%22\"\"sqrt%28%28x%2B4%29%5E2%2B9%29\"\r\n" );
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document.write( "\"%28x%2B1%29%5E2%2B25\"\"%22%22=%22%22\"\"%28x%2B4%29%5E2%2B9\"\r\n" );
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document.write( "\"x%5E2%2B2x%2B1%2B25\"\"%22%22=%22%22\"\"x%5E2%2B8x%2B16%2B9\"\r\n" );
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document.write( "\"x%5E2%2B2x%2B26\"\"%22%22=%22%22\"\"x%5E2%2B8x%2B25\"\r\n" );
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document.write( "\"2x%2B26\"\"%22%22=%22%22\"\"8x%2B25\"\r\n" );
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document.write( "\"1\"\"%22%22=%22%22\"\"6x\"\r\n" );
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document.write( "\"1%2F6\"\"%22%22=%22%22\"\"x\"\r\n" );
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document.write( "So the point on the x-axis is \"%28matrix%281%2C3%2C1%2F6%2C%22%2C%22%2C0%29%29\"\r\n" );
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document.write( "Edwin
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